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COMMON FORMULAS |
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Resistance | Resistances in Series | Voltage Divider | Parallel Resistance | Current Division | Capacitance | Series, Parallel Capacitance Series, Parallel Inductor |
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The resistance R of a circuit is equal to the applied direct voltage V divided by the resulting steady current I:
R = V / I
When resistances R1, R2, R3, ... are connected in series, the total resistance RS is:
RS = R1 + R2 + R3 + ...
Voltage Division by Series Resistances
When a total voltage VS is applied across series connected resistances R1 and R2, the current IS which flows through the
series circuit is:
IS = VS / RS = VS / (R1 + R2)
The voltages V1 and V2 which appear across the respective resistances R1 and R2 are:
V1 = ISR1 = ESR1 / (R1 + R2)
V2 = ISR2 = ESR2 / (R1 + R2)
In general terms, for resistances R1, R2, R3, ... connected in series:
IS = VS / RS = VS / (R1 + R2 + R3 + ...)
Vn = ISRn = VSRn / RS = VSRn / (R1 + R2 + R3 + ...)
Note that the highest voltage drop appears across the highest resistance.
When resistances R1, R2, R3, ... are connected in parallel, the total resistance RP is:
1 / RP = 1 / R1 + 1 / R2 + 1 / R3 + ...
Alternatively, when conductances G1, G2, G3, ... are connected in parallel, the total conductance GP is:
GP = G1 + G2 + G3 + ...
where Gn = 1 / Rn
For two resistances R1 and R2 connected in parallel, the total resistance RP is:
RP = R1R2 / (R1 + R2)
RP = product / sum
The resistance R2 to be connected in parallel with resistance R1 to give a total resistance RP is:
R2 = R1RP / (R1 - RP)
R2 = product / difference
Current Division by Parallel Resistances
When a total current IP is passed through parallel connected resistances R1 and R2, the voltage VP which appears across
the parallel circuit is:
VP = IPRP = IPR1R2 / (R1 + R2)
The currents I1 and I2 which pass through the respective resistances R1 and R2 are:
I1 = VP / R1 = IPR2 / (R1 + R2)
I2 = VP / R2 = IPR1 / (R1 + R2)
In general terms, for resistances R1, R2, R3, ... (with conductances G1, G2, G3, ...) connected in parallel:
VP = IPRP = IP / GP = IP / (G1 + G2 + G3 + ...)
In = VP / Rn = VPGn = IPGn / GP = IPGn / (G1 + G2 + G3 + ...)
where Gn = 1 / Rn
Note that the highest current passes through the highest conductance (with the lowest resistance).
When a voltage is applied to a circuit containing capacitance, current flows to accumulate charge in the capacitance:
Q = òidt = CV
Alternatively, by differentiation with respect to time:
dq/dt = i = C dv/dt
Note that the rate of change of voltage has a polarity which opposes the flow of current.
The capacitance C of a circuit is equal to the charge divided by the voltage:
C = Q / V = òidt / V
Alternatively, the capacitance C of a circuit is equal to the charging current divided by the rate of change of voltage:
C = i / dv/dt = dq/dt / dv/dt = dq/dv
When capacitances C1, C2, C3, ... are connected in series, the total capacitance CS is:
1 / CS = 1 / C1 + 1 / C2 + 1 / C3 + ...
For two capacitances C1 and C2 connected in series, the total capacitance CS is:
CS = C1C2 / (C1 + C2)
CS = product / sum
Capacitances in Parallel
When capacitances C1, C2, C3, ... are connected in parallel, the total capacitance CP is:
CP = C1 + C2 + C3 + ....
When the current changes in a circuit containing inductance, the magnetic linkage changes and induces a voltage in the
inductance:
dy/dt = e = L di/dt
Note that the induced voltage has a polarity which opposes the rate of change of current.
Alternatively, by integration with respect to time:
Y = òedt = LI
The inductance L of a circuit is equal to the induced voltage divided by the rate of change of current:
L = e / di/dt = dy/dt / di/dt = dy/di
Alternatively, the inductance L of a circuit is equal to the magnetic linkage divided by the current:
L = Y / I
Note that the magnetic linkage Y is equal to the product of the number of turns N and the magnetic flux F:
Y = NF = LI
When uncoupled inductances L1, L2, L3, ... are connected in series, the total inductance LS is:
LS = L1 + L2 + L3 + ...
When two coupled inductances L1 and L2 with mutual inductance M are connected in series, the total inductance LS is:
LS = L1 + L2 ± 2M
The plus or minus sign indicates that the coupling is either additive or subtractive, depending on the connection polarity.
Inductances in Parallel
When uncoupled inductances L1, L2, L3, ... are connected in parallel, the total inductance LP is:
1 / LP = 1 / L1 + 1 / L2 + 1 / L3 + ...
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