Then you take a "B" from the stud dog and match it with a "B" from the bitch to fill in the graph.
Now do the same with the "E's". The dog and the bitch are both Ee.
Now you need to find all possible combinations between the two. From the "B" square, we see that the only outcome is Bb. From the "E" square we have several combinations; EE, Ee and ee. So the combinations would present as follows; BbEE, BbEe and Bbee. Then find the combinations on the Genotype chart to see what could be expected.
Black 1 - BBEE carrying no recessive type
Black 2 - BbEE carrying liver
Black 3 - BBEe carrying orange
Black 4 - BbEe carrying liver, orange and lemon
Liver 5 - bbEE carrying no recessive type
Liver 6 - bbEe carrying lemon
Orange 7 - BBee carrying no recessive type
Orange 8 - Bbee carrying lemon
Lemon 9 - bbee carrying no recessive type
So we see that the possible genotypes would be Black 2, Black 4 and Orange 8.
Therefore, according to the phenotype chart the possible outcome would be 75% black and 25% orange colorations produced.