|
B C E f G h I j L P Q |
susceptance capacitance voltage source frequency conductance h-operator current j-operator inductance active power reactive power |
(Siemens) (Farads) (Volts) (Hertz) (Siemens) (1Ð120°) (Amps) (1Ð90°) (Henrys) (Watts) (VArs) |
R S t V W X Z f h w |
resistance apparent power time voltage drop energy reactance impedance phase angle efficiency angular frequency |
(Ohms) (VA) (seconds) (Volts) (Joules) (Ohms) (Ohms) (degrees) (per-unit) (rad/sec) |
Rectangular and polar forms of impedance Z:
Z = R + jX = (R2 + X2)½Ðtan-1(X / R)
= |Z|Ðf = |Z|cosf + j|Z|sinf
Addition of impedances Z1 and Z2:
Z1 + Z2 = (R1 + jX1) + (R2 + jX2)
= (R1 + R2) + j(X1 + X2)
Subtraction of impedances Z1 and Z2:
Z1 - Z2 = (R1 + jX1) - (R2 + jX2)
= (R1 - R2) + j(X1 - X2)
Multiplication of impedances Z1 and Z2:
Z1 * Z2 = |Z1|Ðf1
* |Z2|Ðf2
= ( |Z1| * |Z2| )Ð(f1
+ f2)
Division of impedances Z1 and Z2:
Z1 / Z2 = |Z1|Ðf1
/ |Z2|Ðf2
= ( |Z1| / |Z2| )Ð(f1
- f2)
In summary:
- use the rectangular form for addition and subtraction,
- use the polar form for multiplication and division.
Conversely, an admittance Y comprising a conductance G in parallel with a susceptance B
can be converted to an impedance Z comprising a resistance R in series with a reactance
X:
Z = Y -1 = 1 / (G - jB) = (G + jB) / (G2 + B2)
= G / (G2 + B2) + jB / (G2 + G2) = R + jX
R = G / (G2 + B2) = G / |Y|2
X = B / (G2 + B2) = B / |Y|2
Using the polar form of admittance Y:
Z = 1 / |Y|Ð-f = |Y| -1Ðf
= |Z|Ðf
= |Z|cosf + j|Z|sinf
The total impedance ZS of impedances Z1, Z2,
Z3,... connected in series is:
ZS = Z1 + Z1 + Z1 +...
The total admittance YP of admittances Y1, Y2,
Y3,... connected in parallel is:
YP = Y1 + Y1 + Y1 +...
In summary:
- use impedances when operating on series circuits,
- use admittances when operating on parallel circuits.
Capacitive Reactance
The capacitive reactance XC of a capacitance C at angular frequency
w and frequency f is:
XC = 1 / wC = 1 / 2pfC
At resonance:
XC = XL
ZSr = R
wr = (LC) -½
= 2pfr
Parallel resonance
A parallel circuit comprising an inductance L with a series resistance R connected in parallel
with a capacitance C has an admittance YP of:
YP = 1 / (R + jXL) + 1 / (-jXC)
= (R / (R2 + XL2))
- j(XL / (R2 + XL2) - 1 / XC)
where XL = wL and
XC = 1 / wC
At resonance:
XC = (R2 + XL2) / XL
= XL + R2 / XL
ZPr = YPr-1 = (R2 + XL2) / R
= XLXC / R
= wrL / wrCR = L / CR
wr = (1 / LC - R2 / L2)½
= 2pfr