| C E G I i L M | capacitance voltage source conductance current instantaneous current inductance mutual inductance | (Farads) (Volts) (Siemens) (Amps) (Amps) (Henrys) (Henrys) | P Q R t V v W | power charge resistance time voltage drop instantaneous voltage energy | (Watts) (Coulombs) (Ohms) (seconds) (Volts) (Volts) (Joules) |
The voltages V1 and V2 which appear across the respective resistances
R1 and R2 are:
V1 = ISR1
= ESR1 / (R1 + R2)
V2 = ISR2
= ESR2 / (R1 + R2)
Alternatively, when conductances G1, G2, G3, ... are
connected in parallel, the total conductance GP is:
GP = G1 + G2 + G3 + ...
where G = 1 / R
For two resistances R1 and R2 connected in parallel, the total resistance
RP is:
RP = R1R2 / (R1 + R2)
RP = product / sum
The resistance R2 to be connected in parallel with resistance R1 to give
a total resistance RP is:
R2 = R1RP / (R1 - RP)
R2 = product / difference
The currents I1 and I2 which pass through the respective resistances
R1 and R2 are:
I1 = VP / R1
= IPR2 / (R1 + R2)
I2 = VP / R2
= IPR1 / (R1 + R2)
Alternatively, by differentiation with respect to time:
dQ/dt = I = C dV/dt
The capacitance C of a circuit is equal to the charge divided by the voltage:
C = Q / V = òidt / V
Alternatively, the capacitance C of a circuit is equal to the current divided by the rate of change
of voltage:
C = I / (dV/dt) = (dQ/dt) / (dV/dt) = dQ/dV
The inductance L of a circuit is equal to the induced voltage divided by the rate of change of
current:
L = - E / (di/dt)
The mutual inductance M of two coupled inductances L1 and L2 is
equal to the mutually induced voltage in one inductance divided by the rate of change of current in the other
inductance:
M = - E1 / (di2/dt)
M = - E2 / (di1/dt)
If the coupling between the two inductances is perfect, then:
M = (L1L2)½
When two coupled inductances L1 and L2 with mutual inductance M
are connected in series, the total inductance LS is:
LS = L1 + L2 ± 2M
The plus or minus sign indicates that the coupling is either additive or subtractive, depending on the
connection polarity.
If a voltage E is applied to a series circuit comprising a discharged capacitance C and a
resistance R, then after time t the current i, the voltage vR across
the resistance and the voltage vC across the capacitance are:
i = (E / R)e - t / CR
vR = iR = Ee - t / CR
vC = E - vR = E(1 - e - t / CR)
Inductance and resistance
The time constant of an inductance L and a resistance R is equal to L / R, and
represents the time to change the current in the inductance from zero to E / R at a constant rate of
change of current E / L (which produces an induced voltage E across the inductance).
If a voltage E is applied to a series circuit comprising a pure inductance L and a resistance
R, then after time t the current i, the voltage vR across the
resistance and the voltage vL across the inductance are:
i = (E / R)(1 - e - tR / L)
vR = iR = E(1 - e - tR / L)
vL = E - vR = Ee - tR / L
The energy W consumed by a resistance R carrying a current I due to a voltage E
is:
W = E2t / R = EIt = I2Rt
The energy W stored in a capacitance C holding a voltage V is:
W = ½CV2
The energy W stored in an inductance L carrying a current I is:
W = ½LI2