Tuesday, 18 October

Soffice.bin, 3:06 PM

Untitled4 - OpenOffice.org Writer

Closed Form =

Soffice.bin, 3:06 PM

Untitled4 - OpenOffice.org Writer

k * 2^k + 2^k x+1*(2^x)
( ) k k
Basis: 1+1) ( *(2^1)
2 * (2)
4

Soffice.bin, 3:08 PM

Untitled4 - OpenOffice.org Writer

1

Soffice.bin, 3:08 PM

Untitled4 - OpenOffice.org Writer

0

Soffice.bin, 3:10 PM

Untitled4 - OpenOffice.org Writer

= 2*1 + 2 = 4 = =
4=4

Soffice.bin, 3:11 PM

Untitled4 - OpenOffice.org Writer

Assume =

Soffice.bin, 3:12 PM

Untitled4 - OpenOffice.org Writer

Prove 2S(2^k) + 2 = k+2 * 2^(k+1) ( )

Explorer.exe, 3:14 PM

Untitled window

[Running Applications]

Soffice.bin, 3:14 PM

Untitled4 - OpenOffice.org Writer

2S(

Soffice.bin, 3:15 PM

Untitled4 - OpenOffice.org Writer

2^k) +2

Soffice.bin, 3:15 PM

Untitled4 - OpenOffice.org Writer

^k ^(k+1) +2^k = k+1) ( *(2^k) + (1+1*2^k)
S(2^k) + 2^k =

Waol.exe, 3:17 PM

America Online 9.0 Security Edition SE

hey.
class :(

Waol.exe, 3:18 PM

America Online 9.0 Security Edition SE

good stuff.
I'll get back to it, I hope.

Soffice.bin, 3:18 PM

Untitled4 - OpenOffice.org Writer

(k+1*2^k) ) ( ( ) + ( *(2^1) ( ) + (1+1)*2^1) (