rjrey109: hey
rjrey109: how did u draw the iterations?
emozemoz: enter the equation in the top bar on hte progrram and hit enter
rjrey109: u mean x-y1/nderivy1?
emozemoz: no
emozemoz: the actual function
emozemoz: like 4x-9
rjrey109: yeah..but then when u want to draw the iteration of it
emozemoz: ok they give you the first value right?
emozemoz: then you find the derivative of the function at that point
rjrey109: yeah
emozemoz: find the zero of the tangent line at that point
rjrey109: how do u do that?
emozemoz: find the derivative of the original function
emozemoz: then plug the x value in
rjrey109: ok
rjrey109: so run thru 1a for me
rjrey109: just as an example
rjrey109: i put in x2-3
rjrey109: and it draws a parabola
emozemoz: x0=2.2
y0=1.84
f(x)=x^2-3
f'(x)=2x
f'(x)=4.4
eq of tan line at (2.2,1.84): y=4.4x-7.84
x1=7.84/4.4=1.7818
x1=x0-f(x)/f'(x)
x1=x0-(x0^2-3)/(2*x0)
x1=2.2-(2.2^2-3)/(2*2.2)=1.7818
------
x1=1.7818
y1=.1748
f'(x)=2x
f'(x1)=3.5636
eq of tan line at (1.7818,.1748): y=3.5636x-6.1748
x2=x1-(x1^2-3)/(2*x1)
x2=1.7327
y2=.0024
emozemoz: yeah
emozemoz: that's all of numver one
emozemoz: but hey i gotta get back to typing my extended essay, srry
emozemoz: here's the rest of my work h/o
rjrey109: whoa
rjrey109: ok
emozemoz: http://www.xanga.com/home.aspx?user=balasubasngkamatayan
emozemoz: later
rjrey109: later
rjrey109: 1 quick question though
Auto response from emozemoz: bizzy
rjrey109: how do u save the graph?
emozemoz: print screen and paste to paint
rjrey109: k thanx
Auto response from emozemoz: I am away from my computer right now.
