To reduce the drudgery of the complex computations I have used a simpler two-segment model instead of three segments. One has to trust me that it leads to the same conclusions albeit with substantial less effort.

Hence Fig2b is the simplified configuration used fort the calculations. Fig3 and Fig4 shows the graphically the results of the calculations. The black arrows represent both the amplitude and the direction of the inertial force pulling on the end of the club shaft.

The centrifugal part of the inertial force will get very dominant during the second half of the downswing. However, even if not strictly correct, I will refer to the back arrow as being the centrifugal force for the whole downswing.

Notice in Fig3 that the centrifugal force rapidly aligns itself with the shaft when the clubhead speed is increasing. Fig4 shows the whole downswing and it is clear that the centrifugal force is virtually aligned with the shaft for the second half of the downswing.

We can know answer the question I asked MizunuJoe.The centrifugal line of pull, except for the top part of the down swing, is going through O and C3, both in Fig1b and Fig2b.

mandrin

mandrin