Division by single digit divisor
Division by double digit divisor
Division by 9
2 digits
1|2 ÷ 9 = Q= 1
R= 3
The Quotient will be the first digit of the Dividend
The Remainder will be the sum of the 2 digits of the Dividend.
3 digits
Suppose we have to divide 113 by 9. We will divide 113 into 2 parts so that the units place is in one division the the other 2 digits in the other division.
11|3 ÷ 9 = Q=12
R=5
In the Quotient we bring down the first digit of the dividend as the 1st digit of the quotient and then add the first digit of the quotient to the second digit of the dividend to get the second digit of the quotient. In the remainder we add the second digit of the quotient to the third digit of the dividend.
Suppose we have to divide 111 by 8 :
2`is the complement(10-8) of 8(written under 8). 2 written below the 1 before the stroke is 2(complement)x1(first digit). The 6 written below the 1 after the stroke is 2(complement)x3(complement + first digit). The first digit of the quotient 13 is 1 i.e. the first digit of the dividend. The second digit, 3, is 1(second digit)+2(2x1 mentioned above).
The remainder, 7, is 6(2x3 mentioned above)+1(last digit of dividend).
Suppose we have to divide 123 by 88 :
12 written under 88 is the complement of 88(100-88).
1 the quotient is the first digit of the dividend.
12(complement x first digit) written under 23 is added to 23(last 2 digits of dividend) to give the remainder.
Pythagoras Triplets Multiplication Image Gallery Downloads Home Whole Site
