WE USE THE LAW OF COSINES to solve triangles that are not right-angled. In particular, when we know two sides of a triangle and their included angle, then the Law of Cosines enables us to find the third side. Thus if we know sides a and b and their included angle θ, then the Law of Cosines states:
(The Law of Cosines is a extension of the Pythagorean theorem; because if θ were a right angle, we would have c² = a² + b².)
Proof of the Law of Cosines Let ABC be a triangle with sides a, b, c. We will show c² = a² + b² − 2ab cos C Draw BD perpendicular to CA, separating triangle ABC into the two right triangles BDC, BDA. BD is the height h of triangle ABC. Call CD x. Then DA is the whole b minus the segement x: b − x. Also, since
then x = a cos C . . . . . . . (1) Now, in the right triangle BDC, according to the Pythagorean theorem, h² + x² = a², so that h² = a² − x². . . . . . (2) In the right triangle BDA, c² = h² + (b − x)² c² = h² + b² − 2bx + x² For h², let us substitute line (2): c² = a² − x² + b² − 2bx + x² c² = a² + b² − 2bx Finally, for x, let us substitute line (1): c² = a² + b² − 2b· a cos C That is, c² = a² + b² − 2ab cos C This is what we wanted to prove. In the same way, we could prove that a² = b² + c² − 2bc cos A and b² = a² + c² − 2ac cos B. This is the Law of Cosines. |