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Time
Dilation Observer O' is at rest inside the vehicle. A mirror is fixed to the ceiling. A laser is mounted at distance d below the mirror, on the floor (run animation below for event 1). At some instance, the laser emits a pulse of light toward the mirror (event 1). After reflecting from the mirror, the light pulse arrives back at the laser (event 2). Observer
O' carries a clock C'. Using it, he measured the interval between the
2 events as
This
time is measured by O' who is at rest in the moving vehicle.
Now consider the same set of events observed by a man standing on the land (animation below). To him, the mirror and the laser is moving to the right with a speed v. By the
time the light pulse reaches the mirror, the mirror has moved a distance
Comparing these two situations, we see the light must travel farther in the second case than in the first case. According to second postulate of relativity, both observers must measure the same c for speed of light. Because
the light pulse travels farther in the second case, the time interval
Using Pythagorean
theorem on the triangle in the second case, we obtain a relationship
between
Solving
for
because
where This
result says that the time interval Thus
we can conclude that time between ticks of a moving clock A
moving clock runs slower than a clock at rest by a factor of This applies to all physical processes including chemical reactions and biological processes. Thus if you happen to move in space at a high constant speed with respect to the stationary Earth, your time runs slower and you age slower. |