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CTS papers. |
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Quest of red set.
i)
Series Transformation
1) If 102101->210212 then 112112->?
2) if 102101-> 200111 then 112112->?
Again there r 4 choices.
3) If 102101->101201 then 112112->?
Again there r 4 choices.
Tips:The 1st one all change 0->1, 1->2, 2->1
The 2nd on alternate do not change
The 3rd it is just reverse of the original string
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ii)
Target=127: Brick=24,17,13: Operation available= +,/,*,-
Again there r 4 choices.For ex choice b)20,6,7
Tips:Answer is b one bcos 20*6+7=127.Hence it is the answer
Q:1)U HAVE TO MAKE A TARGET =102; THE ANSWER FROM THE OPTION IS (6,17,2,1)
2)TARGET=41;FIVE NO.S WERE GIVEN;25 22 16 5 1
U CAN USE THE NO.S ONLY ONCE&CAN PERFORM OPERATION +,MULTIPLY,-,/,()ONCE;
OPTIONS WERE;
A)25 22 16 5 B)25 22 16 1 C)25 22 5 1 D)25 16 5 1
4 SUCH QUESTINS ARE THERE.
2)87
3)146
4)127
THERE ARE SOME FIGURATIVE QUESTION;SEE FROM COMPETITION MASTER,I CANT REMEBER
THE FIGURE.4 QUESTIONS ARE THERE
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iii)
Cryptic Sentence. Form word
A sentence is there .a cryptical clue is hidden in the sentence. Find out answer
from the opticn.
1)a friend in rome
a)aerodrome b)palindine c)palindrome d)condome
ans:palindrome
2)Rowed them across
a)crosswiz b)acropolis c)acroword d)crossword
Ans:crossword/crossover
3)cuticle cutting the filly glass
a)cubicle b)uphilly c)cutglass d)cutlass
Ans:cutlass
4)hat jumps upward in a water closet
a)watch b)witch
ans:watch/whatever
Tips:The 1st oneJumble out the word SHORE to get the word HORSE and then get
the adjective of the word HORSE as TROJAN The 2nd one lips->slip->freudian/french
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iv)
Anagram noun form the correesponding adjectives
There re options.
Q:some nouns are jumbled on ,you have to rearrange, look for a suitable
adjective: Make a phrase then.
1)shore
a)aegean b)Indian c)trojan d)Spartan
ans:trojan
2)sire
a)dutch b)rome c)herculean d)mercurial
ans:mercurial
3)ourcage
a)english b)rome c)dutch d)Spartan
ans:Spartan
4)lips
Again there r 4 choices.
Ans:freudian/french
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v)
Jigsaw puzzle as given in the book by Edgar Thorpe, of TMH Publications
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vi)
FUNCTIONS same as CTS_BLACK\fun
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vii)
x , y -> strings of G st there is at least one G in x and y
xoxy valid
xoy->xoxy invalid
Find valid & invalid strings
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